A) \[8\]
B) more than\[8\]
C) between \[6\] and \[7\]
D) slightly more than\[7\]
Correct Answer: C
Solution :
From\[{{H}_{2}}O,\,\,[{{H}^{+}}]=1\times {{10}^{-7}}M\] From\[HCl,\,\,[{{H}^{+}}]=1\times {{10}^{-8}}M\] Total\[[{{H}^{+}}]=(1\times {{10}^{-7}}+1\times {{10}^{-8}})M\] \[=(1\times {{10}^{-7}}+0.1\times {{10}^{-7}})M\] \[=1.1\times {{10}^{-7}}M\] \[pH=-\log (1.1\times {{10}^{-7}})\] \[=6.9586\]
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