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JCECE Engineering JCECE Engineering Solved Paper-2010

  • question_answer
    A \[50\] turn?s Circular coil has a radius of\[3\,\,cm\], it is kept in a magnetic field acting normal to the area of the coil. The magnetic field \[B\] increased from \[0.10\,\,T\] to \[0.35\,\,T\] in \[2\] millisecond. The average induced \[\text{emf}\] in the coil is

    A) \[1.77\,\,V\]                      

    B) \[17.7\,\,V\]

    C)  \[177\,\,V\]                      

    D)  \[0.177\,\,V\]

    Correct Answer: B

    Solution :

    Induced\[emf\,\,e=\frac{-NA({{B}_{2}}-{{B}_{1}})\cos \theta }{\Delta t}\] \[=\frac{50\times \pi \times {{(3\times {{10}^{-2}})}^{2}}[0.35-0.10]\cos {{0}^{o}}}{2\times {{10}^{-3}}}\]\[\Rightarrow \]\[17.7\,\,V\]


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