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JCECE Engineering JCECE Engineering Solved Paper-2010

  • question_answer
    \[0.765\,\,g\] of an acid gives \[0.535\,\,g\] of \[C{{O}_{2}}\] and \[0.138\,\,g\] of. Then, the ratio of the percentage of carbon and hydrogen is

    A) \[19:2\]               

    B) \[18:11\]

    C)  \[20:17\]                            

    D)  \[1:7\]

    Correct Answer: A

    Solution :

    \[%\]of\[C=\frac{12}{44}\times \frac{0.535}{0.765}\times 100=19.07\]   \[%\,\,H=\frac{2}{18}\times \frac{0.138}{0.765}\times 100=2.004\] Ratio of\[%\]\[\text{of}\]\[C:H=19:12\](approx)


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