A) \[1.43\,\,g\]
B) \[2.24\,\,g\]
C) \[11.2\,\,g\]
D) \[22.4\,\,g\]
Correct Answer: A
Solution :
Given, volume of\[{{O}_{2}}=1\,\,L\] \[\because \] \[22.4\,\,L\]of\[{{O}_{2}}\]at\[STP=32\,\,g\] \[\therefore \] \[1\,\,L\]of\[{{O}_{2}}\]at\[STP=\frac{32}{22.4}\,\,g\] \[=1.43\,\,g\]
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