A) \[KI\]
B) \[KCNS\]
C) \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]
D) \[B{{r}_{2}}\]
Correct Answer: A
Solution :
Ether peroxide oxidises \[KI\] into \[{{I}_{2}}\] and itself gets reduced to ether. Therefore, \[KI\] is added to remove peroxides from ethers. \[2{{I}^{-}}\xrightarrow{{}}{{I}_{2}}+2{{e}^{-}}\] Ether peroxide\[+2{{e}^{-}}\xrightarrow{{}}ether+{{O}_{2}}\]
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