A) \[29c\]
B) \[10c\]
C) \[10{{c}^{3}}\]
D) \[20{{c}^{2}}\]
Correct Answer: C
Solution :
We have, \[{{T}_{r+1}}{{=}^{5}}{{C}_{r}}{{({{y}^{2}})}^{5-r}}{{\left( \frac{c}{y} \right)}^{r}}{{=}^{4}}{{C}_{r}}{{y}^{10-3r}}{{c}^{r}}\] Now,\[10-3r=1\Rightarrow r=3\] So, coefficient of\[y{{=}^{5}}{{C}_{3}}\,\,{{c}^{3}}=10{{c}^{3}}\]You need to login to perform this action.
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