A) \[\frac{2}{n}-\frac{1}{{{n}^{2}}}\]
B) \[\frac{1}{{{n}^{2}}}-\frac{1}{n}\]
C) \[\frac{2}{{{n}^{2}}}-\frac{1}{n}\]
D) \[\frac{2}{n}+\frac{1}{{{n}^{2}}}\]
Correct Answer: A
Solution :
Let \[f\] be the uniform acceleration, then \[{{S}_{n}}=\]distance covered in nth second \[=\frac{1}{2}+(n-1)\] and\[S{{'}_{n}}=\]distance covered in \[n\] second\[=\frac{1}{2}+{{n}^{2}}\] \[\therefore \] \[\frac{{{S}_{n}}}{S{{'}_{n}}}=\frac{2n-1}{{{n}^{2}}}=\frac{2}{n}-\frac{1}{{{n}^{2}}}\]
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