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JCECE Engineering JCECE Engineering Solved Paper-2011

  • question_answer
    A body moving with uniform acceleration describes \[12\,\,m\] in the third second of its motion and \[20\,\,m\] in the \[5th\] second. Find the velocity after \[10th\] second.

    A) \[40\,\,m/s\]                    

    B) \[42\,\,m/s\]

    C)  \[52\,\,m/s\]                   

    D)  \[4\,\,m/s\]

    Correct Answer: B

    Solution :

    \[{{S}_{n}}=u+\frac{a}{2}(2n-1)\]                 \[12=u+\frac{a}{2}(2\times 3-1)\]                             ... (i) and        \[20=u+\frac{a}{2}(2\times 5-1)\]                             ... (ii) Subtract Eq. (i) from Eq. (ii)                 \[8=\frac{a}{2}(9-5)=2a\] \[\Rightarrow \]               \[a=4\,\,m/{{s}^{2}}\] From Eq. (i)                 \[12=u+\frac{4}{2}\times 5\]                 \[u=2\,\,m/s\] Velocity\[v=u+at=2+4\times 10\]                 \[=42\,\,m/s\]


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