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JCECE Engineering JCECE Engineering Solved Paper-2011

  • question_answer
    When an electron in hydrogen atom is excited from its 4th to 5th stationary orbit, the change in angular momentum of electron is (Planck's constant\[h=6.6\times {{10}^{-34}}Js)\]

    A) \[4.16\times {{10}^{-34}}Js\]

    B) \[3.32\times {{10}^{-34}}Js\]

    C)  \[1.05\times {{10}^{-34}}Js\]

    D)  \[2.08\times {{10}^{-34}}Js\]

    Correct Answer: C

    Solution :

    \[{{L}_{5}}-{{L}_{4}}=\frac{5h}{2\pi }-\frac{4h}{2\pi }\]                 \[=\frac{h}{2\pi }=\frac{6.6\times {{10}^{-34}}}{2\times 3.14}\]                 \[=1.05\times {{10}^{-34}}Js\]


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