A) \[N{{a}_{2}}O\]
B) \[N{{a}_{2}}{{O}_{2}}\]
C) \[Na{{O}_{2}}\]
D) \[NaO\]
Correct Answer: B
Solution :
When sodium is treated with sufficient oxygen/air, it forms sodium peroxide. \[2Na+{{O}_{2}}\xrightarrow{{}}\underset{sodium\,\,peroxide}{\mathop{N{{a}_{2}}{{O}_{2}}}}\,\]
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