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JCECE Engineering JCECE Engineering Solved Paper-2012

  • question_answer
    A monkey of \[25\,\,kg\] is holding a vertical rope. The rope does not break if a body of mass \[30\,\,kg\] is suspended from it, but the rope breaks if the mass of body suspended with the rope exceeds\[30\,\,kg\]. What will be the maximum acceleration with which the monkey can climb up along the rope?

    A) \[2.0\,\,m{{s}^{-2}}\]                    

    B) \[2.5\,\,m{{s}^{-2}}\]

    C)  \[3.0\,\,m{{s}^{2}}\]                     

    D)  \[4.0\,\,m{{s}^{-2}}\]

    Correct Answer: A

    Solution :

    The maximum weight which can be suspended with the rope without breaking it\[=30\,\,kg\,\,wt\].                 \[=30\times 10=300\,\,N\] \[\therefore \]  \[300\,\,N=mg+ma\] or            \[ma=300-mg=300-25\times 10=50\,\,N\] or            \[a=\frac{50}{m}=\frac{50}{25}=2.0\,\,m{{s}^{-2}}\]


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