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JCECE Engineering JCECE Engineering Solved Paper-2012

  • question_answer
    Equation of the chord of the hyperbola \[25{{x}^{2}}-16{{y}^{2}}=400\] which is bisected at the point \[(6,\,\,2)\] is

    A) \[16x-75y=418\]              

    B) \[75x-16y=418\]

    C) \[25x-4y=400\] 

    D)  None of these

    Correct Answer: B

    Solution :

    Equation of hyperbola is                 \[25{{x}^{2}}-16{{y}^{2}}=400\] \[\Rightarrow \]               \[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{25}=1\] Chord is bisected at\[(6,\,\,2)\]. \[\therefore \]  \[\frac{6x}{16}-\frac{2y}{25}=\frac{{{6}^{2}}}{16}-\frac{{{2}^{2}}}{25}\] \[\Rightarrow \]               \[\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{25}=1\]


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