A) \[{{0}^{o}}C\]
B) \[-{{10}^{o}}C\]
C) \[{{10}^{o}}C\]
D) \[{{40}^{o}}C\]
Correct Answer: B
Solution :
Temperature gradient\[=\frac{{{\theta }_{1}}-{{\theta }_{2}}}{l}\] Here, \[{{\theta }_{1}}={{30}^{o}}C\] \[l=0.5\,\,m\] \[\therefore \] \[80=\frac{30-{{\theta }_{2}}}{0.5}\] \[{{\theta }_{2}}=30-80\times 0.5\] \[\Rightarrow \] \[{{\theta }_{2}}=30-40=-{{10}^{o}}C\]
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