• # question_answer A solution of sucrose (molar mass$~=342gmo{{l}^{-1}})$ has been prepared by dissolving $68.5\,\,g$ of sucrose in $1000\,\,g$ of water. The freezing point of solution obtained will be (${{K}_{f}}$for water$=1.86\,\,K\,\,kg\,\,mo{{l}^{-1}})$ A) $-{{0.570}^{o}}C$                          B) $-{{0.372}^{o}}C$ C) $-{{0.520}^{o}}C$                          D)  $+{{0.372}^{o}}C$

$\Delta {{T}_{f}}=\frac{1000\times {{K}_{f}}\times {{w}_{2}}}{{{M}_{2}}\times {{w}_{1}}}$         $=\frac{1000\times 1.86\times 68.5}{342\times 1000}={{0.372}^{o}}C$                 $\Delta {{T}_{f}}=T_{f}^{o}-\Delta {{T}_{f}}=0-0.372={{0.372}^{o}}C$