A) \[\frac{a}{x}+\frac{b}{y}+\frac{c}{z}=1\]
B) \[\frac{a}{x}+\frac{b}{y}+\frac{c}{z}=1\]
C) \[\frac{a}{x}+\frac{b}{y}+\frac{c}{z}=-2\]
D) \[\frac{a}{x}+\frac{b}{y}+\frac{c}{z}=-1\]
Correct Answer: B
Solution :
Let plane is\[\frac{x}{{{x}_{1}}}+\frac{y}{{{y}_{1}}}+\frac{z}{{{z}_{1}}}=1\]. which passes through\[(a,\,\,b,\,\,c)\] \[\therefore \] \[\frac{a}{{{x}_{1}}}+\frac{b}{{{y}_{1}}}+\frac{c}{{{z}_{1}}}=1\] \[\therefore \] Locus of\[({{x}_{1}},\,\,{{y}_{1}},\,\,{{z}_{1}})\]is\[\frac{a}{x}+\frac{b}{y}+\frac{c}{z}=1\]
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