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JCECE Engineering JCECE Engineering Solved Paper-2013

  • question_answer
    For a transistor in common base, the current gain is\[~0.95\]. If the load resistance is \[400\,\,k\Omega \] and input resistance is \[200\,\,k\Omega \], then the voltage gain and power gain will be

    A)  1900 and 1800                  

    B)  1900 and 1805

    C)   5525 and 3591                 

    D)   1805 and 1900

    Correct Answer: B

    Solution :

    Given,\[\alpha =0.95\],    \[{{R}_{0}}=400\times {{10}^{3}}\Omega \]           \[{{R}_{i}}=200\Omega \] As, voltage gain \[=\alpha \frac{{{R}_{0}}}{{{R}_{i}}}=0.95\times \frac{400\times {{10}^{3}}}{200}=1900\] Power gain = Voltage gain \[\times \] Current gain                       \[=1900\times 0.95=1805\]


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