A) \[C{{N}^{-}},\,\,{{O}_{3}}\]
B) \[Cl{{O}_{2}},\,\,Br{{F}_{2}}\]
C) \[BrO_{2}^{-},\,\,BrF_{2}^{+}\]
D) \[IC{{I}_{2}},\,\,Cl{{O}_{3}}\]
Correct Answer: C
Solution :
Both\[BrO_{2}^{-}(35+2\times 8+1=52)\]and \[BrF_{2}^{+}(35+2\times 9-1=52)\] have 52 electrons.
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