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JCECE Engineering JCECE Engineering Solved Paper-2014

  • question_answer
    The equation of the plane containing the line of intersection of the planes \[2x-y=0\] and \[y-3z=0\] and perpendicular to the plane \[4x+5y-3z-8=0\] is

    A) \[28x-17y+9z=0\]            

    B) \[28x+17y+9z=0\]

    C)  \[28x-17y-9z=0\]            

    D) \[7x-3y+z=0\]

    Correct Answer: A

    Solution :

    Equation of plane containing the line of intersection of planes is                 \[(2x-y)+\lambda (y-3z)=0\]                       ... (i) Also, plane (i) is perpendicular to                 \[4x+5y-3z-8=0\] \[\therefore \]  \[4(2)+5(\lambda -1)-3(-3\lambda )=0\] \[\Rightarrow \]                                               \[14\lambda =-3\] \[\Rightarrow \]                                               \[\lambda =\frac{-3}{14}\] Putting the value of 'k in Eq. (i), we get                 \[28x-17y+9z=0\] which is the required plane.


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