A) \[0.8\,\,g/cc\]
B) \[1.2\,\,g/cc\]
C) \[1.4\,\,g/cc\]
D) \[1.6\,\,g/cc\]
Correct Answer: A
Solution :
Its shown in figure, in the two arms of a tube pressure remains same on surface\[pp'\] Hence, \[8\times {{\rho }_{y}}\times g+2\times {{\rho }_{Hg}}=10\times {{\rho }_{x}}\times g\] \[8\times {{\rho }_{y}}+2\times 13.6=10\times 33.6\] \[{{\rho }_{y}}=\frac{33.6-27.2}{8}=0.8\,\,g/cc\]
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