A) \[\pm \sqrt{5}\]
B) \[\pm \sqrt{6}\]
C) \[\pm \sqrt{7}\]
D) None of these
Correct Answer: C
Solution :
Given, \[x\] is parallel to\[y\]and\[z\] \[\therefore \] \[\mathbf{x}\cdot (\mathbf{y}\times \mathbf{z})=0\Rightarrow [\mathbf{x}\,\mathbf{y}\,\mathbf{z}]=0\] \[\Rightarrow \] \[\left| \begin{matrix} 2 & 1 & \alpha \\ \alpha & 0 & 1 \\ 5 & -1 & 0 \\ \end{matrix} \right|=0\] \[\Rightarrow \] \[2(0+1)-1(0-5)+\alpha (-\alpha -0)=0\] \[\Rightarrow \] \[2+5-{{\alpha }^{2}}=0\] \[\Rightarrow \] \[{{\alpha }^{2}}=7\] \[\Rightarrow \] \[\alpha =\pm \sqrt{7}\]You need to login to perform this action.
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