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JCECE Engineering JCECE Engineering Solved Paper-2014

  • question_answer
    Two monoatomic ideal gases \[A\] and \[B\] occupying the same volume \[V\] are at the same temperature \[T\] and pressure\[p\]. If they are mixed, the resultant mixture has volume \[V\] and temperature\[T\]. The pressure of the mixture is

    A) \[p\]                                     

    B) \[\frac{p}{2}\]

    C) \[4p\]                                   

    D)  \[2p\]

    Correct Answer: D

    Solution :

                    \[\frac{{{p}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{p}_{mix}}\times {{V}_{mix}}}{{{T}_{mix}}}\]                 \[{{T}_{1}}={{T}_{mix}}=T\]                 \[{{V}_{1}}=V+V\]                 \[{{V}_{mix}}=V\]                 \[\frac{p\times 2V}{T}=\frac{{{p}_{mix}}}{T}\times V\]                 \[{{p}_{mix}}=2p\]


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