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JCECE Engineering JCECE Engineering Solved Paper-2014

  • question_answer
    \[U\] is the \[PE\] of an oscillating particle and \[F\] is the force acting on it at a given instant. Which of the following is true?

    A) \[\frac{U}{F}+x=0\]                        

    B) \[\frac{2U}{F}+x=0\]

    C) \[\frac{F}{U}+x=0\]                        

    D)  \[\frac{F}{2U}+x=0\]

    Correct Answer: B

    Solution :

    Potential energy of an oscillating particle                 \[U=\frac{1}{2}k{{x}^{2}}\]                 \[2U=k{{x}^{2}}\]                 \[2U=-kx\]                 \[\frac{2U}{F}=-x\]or\[\frac{2U}{F}+x=0\]


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