A) \[6\]
B) \[14\]
C) \[16\]
D) \[18\]
Correct Answer: B
Solution :
Magnification\[\frac{{{f}_{0}}}{{{f}_{e}}}=10\] or \[{{f}_{0}}=10{{f}_{e}}\] \[{{f}_{0}}+{{f}_{e}}=1.1\,\,m\] \[{{f}_{e}}+10{{f}_{e}}=1.1\times 100\,\,cm\] \[11{{f}_{e}}=110\] \[{{f}_{e}}=10\] Magnification least distance of distant vision \[{{M}_{b}}=\frac{{{f}_{0}}}{{{f}_{e}}}\left( 1+\frac{{{f}_{e}}}{{{f}_{s}}} \right)\] \[=10\left( 1+\frac{10}{25} \right)=10\left( \frac{35}{25} \right)=14\]
You need to login to perform this action.
You will be redirected in
3 sec
