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JCECE Engineering JCECE Engineering Solved Paper-2014

  • question_answer
    A gardener pushes a lawn roller through distance\[20\,\,m\]. If he applies a force of \[20\,\,kg-w\] in a direction inclined at \[{{60}^{o}}\] to the ground, the work done by him is

    A) \[1960\,\,J\]                      

    B) \[196\,\,J\]

    C) \[1.96\,\,J\]                       

    D) \[196\,\,kJ\]

    Correct Answer: A

    Solution :

    \[F=20\,\,kg-wt=20\times 9.8\,\,N\]                 \[\theta ={{60}^{o}}\]and\[s=20\,\,m\] Work done\[=Fs\cos \theta \]                 \[=20\times 9.8\times 20\times \cos {{60}^{o}}\]                 \[=1960\,\,J\]


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