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JCECE Engineering JCECE Engineering Solved Paper-2014

  • question_answer
    \[Li\] nucleus has three protons and four neutrons. Mass of lithium nucleus is\[7.016005\,\,amu\]. Mass of proton is \[1.007277\,\,amu\] and mass of neutron is\[1.008665\,\,amu\]. Mass defect for lithium nucleus in \[amu\] is

    A) \[0.04048\]

    B) \[0.04050\]

    C) \[0.04052\]

    D) \[0.04055\]

    Correct Answer: B

    Solution :

    Mass defect = mass of nucleons - mass of nucleus \[=(3\times 1.007277+41.008665)-7.016005\] \[=0.040486\,\,amu\]\[\approx 0.04050\]


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