A) \[HSO_{4}^{-}\]
B) \[N{{a}_{2}}C{{O}_{3}}\]
C) \[N{{H}_{3}}\]
D) \[O{{H}^{-}}\]
Correct Answer: A
Solution :
\[HSO_{4}^{-}\] can accept proton to form \[{{H}_{2}}S{{O}_{4}}\] and also give a proton to form \[SO_{4}^{2-}\] therefore it acts both as Bronsted acid as well as base.
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