A) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{2}}-C{{H}_{2}}-CHO\] (4-methyl-1-pentanal)
B) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,H-C\equiv C-COOH\] (4-methyl-2-pentyn-1-oic acid)
C) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,H-COOH\] (2-methyl-1-pentanoic acid)
D) \[C{{H}_{3}}C{{H}_{2}}-CH=CH-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\] (3-hexen-5-one)
Correct Answer: D
Solution :
\[\overset{6}{\mathop{C}}\,{{H}_{3}}-\overset{5}{\mathop{C}}\,{{H}_{2}}-\overset{4}{\mathop{C}}\,H=\overset{3}{\mathop{C}}\,H{{-}^{2}}\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-\overset{1}{\mathop{C}}\,{{H}_{3}}\] 3-hexen-2-one
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