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JCECE Engineering JCECE Engineering Solved Paper-2014

  • question_answer
    \[Phenol\xrightarrow[(ii)\,\,C{{O}_{2}}/{{140}^{o}}C]{(i)\,\,NaOH}A\xrightarrow{{{H}^{+}}/{{H}_{2}}O}B\xrightarrow{A{{c}_{2}}O}C\]In this reaction, the end product \['C'\] is

    A)  salicylaldehyde               

    B)  salicylic acid

    C)   phenyl acetate               

    D)   aspirin

    Correct Answer: D

    Solution :


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