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JCECE Engineering JCECE Engineering Solved Paper-2015

  • question_answer
    The binding energy per nucleon of \[{{C}^{12}}\] is \[{{E}_{1}}\] and that of \[{{C}^{13}}\] is\[{{E}_{2}}\]. The energy required to remove one neutron from \[{{C}^{13}}\] is

    A) \[12{{E}_{1}}+12{{E}_{2}}\]                         

    B) \[13{{E}_{2}}-12{{E}_{1}}\]

    C) \[12{{E}_{2}}-13{{E}_{1}}\]                          

    D) \[13{{E}_{2}}+12{{E}_{1}}\]

    Correct Answer: B

    Solution :

    Binding energy of \[{{C}^{12}}\] is                 \[B{{E}_{1}}=12\times {{E}_{1}}\] Binding energy of \[{{C}^{13}}\] is                 \[B{{E}_{2}}=13\times {{E}_{2}}\] Thus, energy required to remove one neutron from\[{{C}^{13}}\]is,                 \[\Delta E=B{{E}_{2}}-B{{E}_{1}}=13{{E}_{2}}-12{{E}_{1}}\]


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