A) acetaldehyde
B) acetylene
C) ethylene
D) acetylchloride
Correct Answer: C
Solution :
\[\underset{Acetic\,\,acid}{\mathop{C{{H}_{3}}COOH}}\,\xrightarrow{LiAl{{H}_{4}}}\underset{\begin{smallmatrix} Ethanol \\ (A) \end{smallmatrix}}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,\xrightarrow{PC{{l}_{5}}}\] \[\begin{align} & C{{H}_{3}}C{{H}_{2}}Cl+POC{{l}_{3}}+HCl \\ & Ethyl\,\,chloride \\ & \begin{matrix} \begin{align} & \text{Elimination} \\ & \operatorname{Reaction} \\ \end{align} & \downarrow & Alc.\,\,KOH \\ \end{matrix} \\ \end{align}\] \[\underset{\begin{smallmatrix} Ethylene\,\,chloride \\ (C) \end{smallmatrix}}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\]
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