\[A\]and \[B\] are respectively.
A) \[{{H}_{2}}/Pt;\,\,LiAl{{H}_{4}}/{{H}_{2}}O\]
B) \[{{H}_{2}}/Pt;\,\,{{H}_{2}}/Pt\]
C) \[LiAl{{H}_{4}}/{{H}_{2}}O;\,\,LiAl{{H}_{4}}/{{H}_{2}}O\]
D) \[LiAl{{H}_{4}}/{{H}_{2}}O;\,\,{{H}_{2}}/Pt\]
Correct Answer: D
Solution :
\[LiAl{{H}_{4}}\] does not attack \[(C=O)\] bond, whereas \[{{H}_{2}}/Pt\]reduced it into\[(-C-OH)\].
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