A) octahedral
B) tetrahedral
C) trigonal bipyramidal
D) square planar
Correct Answer: C
Solution :
Key Idea: Write the name of orbitals which are participating in bond formation and then calculate percentage.| Hybridisation | Orbitals | % of s character |
| Octahedral | \[s{{p}^{3}}{{d}^{2}}\] | 16.7% |
| Tetrahedral | \[s{{p}^{3}}\] | 25% |
| Trigonal bipyramidal | \[s{{p}^{3}}d\] | 20% |
| Square planar | \[s{{p}^{3}}{{d}^{2}}\] | 16.7% |
You need to login to perform this action.
You will be redirected in
3 sec
