A) \[+\,14\,\text{to}+4\]
B) \[+\,6\,\text{to}+2\]
C) \[-7\,\text{to}-2\]
D) \[+7\,\text{to}+2\]
Correct Answer: D
Solution :
Key Idea: The sum of oxidation number of all elements in an ion is equal to charge on ion. In the reaction \[\text{MnO}_{4}^{-}\]changes into \[\text{M}{{\text{n}}^{\text{2+}}}\] Let oxidation state of Mn in \[\text{MnO}_{4}^{-}=x\] \[\therefore \] \[x+(4x-2)=-1\] \[\therefore \] \[x=+\,7\] Oxidation state of Mn in\[M{{n}^{2+}}=+\,2\] \[\therefore \]the oxidation number of Mn changes from + 7 to +2 during reaction.
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