JCECE Medical JCECE Medical Solved Paper-2003

  • question_answer
    Two identical batteries, each of emf 2 V and internal resistance \[1\,\Omega \]pass a current through external resistance \[R=0.5\,\Omega .\]The maximum power that can be developed across R using these batteries is:

    A)  3.2W           

    B)  8.2W

    C)  4 W             

    D)  2 W

    Correct Answer: D

    Solution :

     Key Idea: In pardllel combination positive poles of all cells are connected to one point and negative poles to another point. The resistances of \[1\,\Omega \] are connected in parallel hence, equivalent resistance of combination is \[{{r}_{eq}}=\frac{1\times 1}{1+1}=0.5\] From Ohms law, \[E=i(R+r)\] \[\therefore \] \[i=\frac{2}{0.5+0.5}=2A\] Power is given by \[P={{i}^{2}}R={{(2)}^{2}}\times 0.5=2W\]


You need to login to perform this action.
You will be redirected in 3 sec spinner