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JCECE Medical JCECE Medical Solved Paper-2003

  • question_answer
    The volume of a gas is reduced to 1.0 L at \[\text{25}{{\,}^{\text{o}}}\text{C}\]and 1 atm. pressure. Its pressure at \[\text{35}{{\,}^{\text{o}}}\text{C}\]would  be:

    A)  0.96 atm       

    B)  1.03 atm

    C)  2.04 atm       

    D)  3.08 atm

    Correct Answer: B

    Solution :

     Key Idea: \[\frac{{{P}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}}{{{T}_{2}}}\] Given \[{{P}_{1}}=1\,\text{atm,}\,{{P}_{2}}=?\] \[{{T}_{1}}=25{{\,}^{o}}C=25+273=298K\] \[{{T}_{2}}=35{{\,}^{o}}C=35+273=308K\] \[\frac{1}{298}=\frac{{{P}_{2}}}{308}\] or \[{{P}_{2}}=\frac{308}{298}=1.03\,\text{atm}\]


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