A) 2
B) 2.5
C) 1.5
D) 0.5
Correct Answer: B
Solution :
Key Idea: Write electronic configuration of \[\text{O}_{\text{2}}^{\text{+}}\] according to molecular orbital theory and then calculate bond order. \[\text{O}_{\text{2}}^{\text{+}}=8+8-1=15\] \[\sigma 1{{s}^{2}},{{\sigma }^{*}}1{{s}^{2}},\sigma 2{{s}^{2}},{{\sigma }^{*}}2{{s}^{2}},\sigma 2p_{z}^{2},\pi 2p_{x}^{2},\] \[\pi 2p_{y}^{2},{{\pi }^{*}}2p_{x}^{1}\] Bond order \[=\frac{1}{2}\][number of bonding electrons - number of antibonding electrons] \[=\frac{1}{2}(10-5)=\frac{5}{2}=2.5\]
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