JCECE Medical JCECE Medical Solved Paper-2003

  • question_answer
    If the equation of motion of standing wave is \[y=0.3\,\sin (314\,t-1.57x),\]then the velocity of standing wave is:

    A)  400 unit       

    B)  350 unit

    C)  209 unit      

    D)    200 unit

    Correct Answer: D

    Solution :

     Key Idea: Standard equation of standing wave is               \[y=a\sin (\omega t-kx)\] The given equation is \[y=0.3\,\sin (314t-1.57\,x)\] On comparing the two equations, we have \[\omega t=314\,t\] and \[kx=1.57\,x\] \[\Rightarrow \] \[\omega =314\] and \[k=1.57\] Hence, velocity of standing wave is \[v=\frac{\omega }{k}=\frac{314}{1.57}=200\,\text{unit}\text{.}\]


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