• # question_answer A parallel plate capacitor is immersed in an oil of dielectric constant 2. The field between the plates is: A)  decreased, by a factor of$\frac{1}{\sqrt{2}}$ B)  increased, by a factor of $\sqrt{2}$ C)  increased, by a factor of$\frac{1}{2}$ D)  decreased, by a factor of 2

When a dielectric material is inserted between the plates of a capacitor (keeping the charge to be constant) or capacitor is immersed in dielectric medium, the electric field decreases  by a factor k (the dielectric constant of the dielectric) $\therefore$ $E=\frac{{{E}_{0}}}{k}$ Given, $k=2$ Hence, $E=\frac{{{E}_{0}}}{2}$ Thus, electric field between the plates is decreased by a factor of 2.