A) 1 : 2
B) 2 : 1
C) 1:1
D) 4:1
Correct Answer: A
Solution :
Key Idea: The potential energy of satellite is twice its kinetic energy but opposite in sign. Potential energy, \[U=-\frac{G{{M}_{e}}m}{{{R}_{e}}}or|U|=\frac{G{{M}_{e}}m}{{{R}_{e}}}\] Kinetic energy, \[K=\frac{1}{2}\frac{G{{M}_{e}}m}{{{R}_{e}}}\] Thus, \[\frac{K}{|U|}=\frac{1}{2}\frac{G{{M}_{e}}m}{{{R}_{e}}}\times \frac{{{R}_{e}}}{G{{M}_{e}}m}=\frac{1}{2}\]
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