A) 0.0195 g
B) 0.0013 g
C) 0.020 g
D) 0.0020 g
Correct Answer: B
Solution :
Key Idea: According to Faradays first law of electrolysis. \[w=Zit\] or \[=\frac{E}{F}it\] \[\left( \because \,Z=\frac{E}{F} \right)\] \[=\frac{E}{F}\times q\] \[(\because \,it=q)\] Given\[~q=4\] coulomb \[E\]for \[Cu=31.75\] \[\therefore \] \[w=\frac{31.75}{96500}\times 4\] \[=0.0013\,g\]
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