JCECE Medical JCECE Medical Solved Paper-2005

  • question_answer
    Three point charges 1C, 2C and 3 C are placed at the corners of an equilateral triangle of side 1m. The work done in bringing these charges to the vertices of a smaller similar triangle of side 0.5 m is:

    A) \[2.7\times {{10}^{10}}\,J\]

    B)  \[9.9\times {{10}^{10}}\,J\]

    C)  \[10.8\times {{10}^{10}}\,J\]

    D) \[5.4\times {{10}^{10}}\,J\]

    Correct Answer: B

    Solution :

     Key Idea: Work done is equal to potential energy. Potential energy \[(U)\] is given by \[U=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{r}\] For three sets of charges \[U={{U}_{1}}+{{U}_{2}}+{{U}_{3}}=\frac{1}{4\pi {{\varepsilon }_{0}}}.\] \[({{q}_{1}}{{q}_{2}}+{{q}_{2}}{{q}_{3}}+{{q}_{3}}{{q}_{1}}).\frac{1}{r}\] \[\Rightarrow \]\[U=\frac{1}{4\pi {{\varepsilon }_{0}}}(1\times 2+2\times 3+3\times 1)\left( \frac{1}{0.5}-\frac{1}{1} \right)\] \[=9\times {{10}^{9}}\times 11\] \[=9.9\times {{10}^{10}}J\]


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