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JCECE Medical JCECE Medical Solved Paper-2006

  • question_answer
    A body cools from \[\text{75}{{\,}^{\text{o}}}\text{C}\]to \[\text{70}{{\,}^{\text{o}}}\text{C}\]in time \[{{t}_{1}},\]from \[\text{70}{{\,}^{\text{o}}}\text{C}\]to \[65{{\,}^{o}}C\]in time\[{{t}_{2}}\]and from \[65{{\,}^{o}}C\]to \[60{{\,}^{o}}C\]in time \[{{t}_{3}},\] then:             

    A) \[{{t}_{3}}>{{t}_{2}}>{{t}_{1}}\]

    B)  \[{{t}_{1}}>{{t}_{2}}>{{t}_{3}}\]

    C)  \[{{t}_{2}}>{{t}_{1}}={{t}_{3}}\]

    D)  \[{{t}_{1}}>{{t}_{2}}>{{t}_{3}}\]

    Correct Answer: A

    Solution :

     From Newtons law of cooling \[\frac{dH}{dt}=K\left( \frac{{{\theta }_{1}}+{{\theta }_{2}}}{2}-{{\theta }_{0}} \right)\] where \[{{\theta }_{0}}\]is temperature of surrounding, \[\frac{{{\theta }_{1}}+{{\theta }_{2}}}{2}\] the temperature of body. Hence, \[{{t}_{3}}>{{t}_{2}}>{{t}_{1}}.\]


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