A) 4 A
B) 1.56 A
C) 5.6 A
D) 1.41 A
Correct Answer: C
Solution :
The peak value of current \[({{I}_{0}})\]is given by \[{{I}_{0}}=\sqrt{2}\,{{I}_{rms}}\] where\[{{I}_{rms}}\]is known as root mean square value of current Given, \[{{I}_{rms}}=4A\] \[\therefore \] \[{{I}_{0}}=\sqrt{2}\times 4=5.6A\]
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