JCECE Medical JCECE Medical Solved Paper-2006

  • question_answer
    If path difference becomes \[(2n-1)\frac{\lambda }{2}\]then: 2»

    A)  white fringe is formed

    B)  bright fringe is formed

    C)  uniform illumination is obtained

    D)  dark fringe is formed

    Correct Answer: D

    Solution :

     Key Idea: Path difference is odd multiple of \[\frac{\lambda }{2}.\] Given path difference \[=(2n-1)\frac{\lambda }{2}\] which is an odd multiple of \[\frac{\lambda }{2}.\] Hence, destructive interference takes place  and dark fringe is formed.


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