A) \[~2x-y\]
B) \[~2x+y\]
C) \[~x+y\]
D) \[\frac{2x-y}{2}\]
Correct Answer: A
Solution :
Given: \[S+\frac{3}{2}{{O}_{2}}\xrightarrow{{}}S{{O}_{3}}\] \[\Delta n=2x\] ?(i) \[S{{O}_{2}}+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}S{{O}_{3}}\] \[\Delta n=y\] ?(ii) Heat of formation of \[\text{S}{{\text{O}}_{\text{2}}}\]can be calculated by reversing the Eq. (ii) and then adding the Eqs. (i) and (iii). \[S{{O}_{3}}\xrightarrow{{}}S{{O}_{2}}+\frac{1}{2}{{O}_{2}}-y\] ?(iii) Now, by adding the Eqs. (i) and (ii) \[\begin{align} & S+\frac{3}{2}{{O}_{2}}\xrightarrow{{}}S{{O}_{3}}+2x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...(i) \\ & \underline{\,\,\,\,\,\,\,\,S{{O}_{3}}\xrightarrow{{}}\,S{{O}_{2}}+\frac{1}{2}{{O}_{2}}-y}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...(ii) \\ & S\,+{{O}_{2}}\xrightarrow{{}}S{{O}_{2}}+(2x-y)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...(iii) \\ \end{align}\] So, heat of formation of \[\text{S}{{\text{O}}_{\text{2}}}\]is \[2x-\text{ }y.\]
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