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JCECE Medical JCECE Medical Solved Paper-2006

  • question_answer
    The two capacitors \[{{\text{C}}_{\text{1}}}\]and \[{{\text{C}}_{\text{2}}}\]are charged to potentials\[{{\text{V}}_{1}}\]and\[{{\text{V}}_{2}}\] and then connected in parallel. There will be no flow of energy, if:

    A) \[{{C}_{1}}{{V}_{1}}={{C}_{2}}{{V}_{2}}\]

    B)  \[{{V}_{1}}={{V}_{2}}\]

    C)  \[{{C}_{1}}=C{{  }_{2}}\]

    D)  \[\frac{{{C}_{1}}}{{{V}_{1}}}=\frac{{{C}_{2}}}{{{V}_{2}}}\]

    Correct Answer: B

    Solution :

     When a conductor of capacitance C is charged, it acquires a potential \[V=\frac{q}{C}\] When connected in parallel, equivalent capacitance of combination is \[C={{C}_{1}}+{{C}_{2}}\] Also, energy, flow \[\left( E=\frac{1}{2}C{{V}^{2}} \right)\] will not take place, if potential across capacitors is same.


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