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JCECE Medical JCECE Medical Solved Paper-2008

  • question_answer
    For the redox reaction \[Zn(s)+C{{u}^{2+}}(0.1\,M)\xrightarrow{{}}Z{{n}^{2+}}(1.M)+Cu(s)\] taking place in a cell, \[\text{E}_{\text{cell}}^{\text{o}}\]is\[\text{1}\text{.10}\,\text{V}\text{.}{{\text{E}}_{\text{cell}}}\] for the cell will be \[\left( 2.303\frac{RT}{F}=0.0591 \right)\]

    A)  2.14 V          

    B)  1.80 V

    C)  1.07 V          

    D)  0.82 V

    Correct Answer: C

    Solution :

     \[{{E}_{cell}}=E_{cell}^{o}-\frac{0.0591}{n}\log \,Q\] \[\underset{0.1\,M}{\mathop{C{{u}^{2+}}}}\,+Zn\xrightarrow{{}}\underset{1\,M}{\mathop{Z{{n}^{2+}}}}\,+Cu\] \[Q=\frac{[Z{{n}^{^{2+}}}]}{[C{{u}^{2+}}]}=\frac{1}{0.1}=10\] \[{{E}_{cell}}=1.10-\frac{0.0591}{2}\log 10\] \[=1.10-0.0295=1.0705\,V\]


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