JCECE Medical JCECE Medical Solved Paper-2008

  • question_answer In this reaction \[C{{H}_{3}}CHO+HCN\xrightarrow{{}}C{{H}_{3}}CH(OH)CN\] \[\xrightarrow{\text{H}\text{.OH}}C{{H}_{3}}CH(OH)COOH\] an asymmetric centre is generated. The acid obtained would be

    A)  50% D + 50% L-isomer

    B)  20% D + 80% L-isomer

    C)  D-isomer

    D)  L-isomer

    Correct Answer: A

    Solution :

     Lactic acid obtained in the given reaction is an optically active compound due to the presence of chiral C-atom. It exists as d and \[l\] forms whose ratio is 1:1. \[\underset{50%\,\text{L}-\text{isomer}}{\mathop{H-\underset{CN}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-OH}}\,\,\,\,\,\,+\,\,\,\,\,\,\underset{50%\,D\,-\text{isomer}}{\mathop{HO-\underset{CN}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-H}}\,\]


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