A) \[15\,L\,\]of \[{{H}_{2}}\]gas at STP
B) \[5\,L\,\]of \[{{N}_{2}}\]gas at STP
C) \[0.5\,g\,\]of \[{{H}_{2}}\]gas
D) \[10\,g\]of \[{{O}_{2}}\]gas
Correct Answer: A
Solution :
In 15 L of \[{{\text{H}}_{\text{2}}}\]gas at STP, the number of molecules \[=\frac{6.023\times {{10}^{23}}}{22.4}\times 15\] \[=4.033\times {{10}^{23}}\] In 5 L of \[{{\text{N}}_{\text{2}}}\]gas at STP, the number of molecules \[=\frac{6.023\times {{10}^{23}}\times 5}{22.4}\] \[=1.344\times {{10}^{23}}\] In 0.5 g of \[{{\text{H}}_{\text{2}}}\]gas, the number of molecules \[\text{=}\,\frac{6.023\times {{10}^{23}}\times 0.5}{2}\] \[=1.505\times {{10}^{23}}\] In 10 g of \[{{\text{O}}_{\text{2}}}\] gas, the number of molecules \[=\frac{6.023\times {{10}^{23}}\times 10}{32}\] \[=1.882\times {{10}^{23}}\] Hence, maximum molecules are present in 15 L of \[{{\text{H}}_{\text{2}}}\]at STP.
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