A) \[_{28}^{59}Ni\]
B) \[_{27}^{59}Co\]
C) \[_{28}^{60}Ni\]
D) \[_{27}^{60}Co\]
Correct Answer: C
Solution :
\[_{28}^{60}Ni+\underset{(n)}{\mathop{_{0}^{1}n}}\,\xrightarrow{{}}_{27}^{60}Co+\underset{(p)}{\mathop{_{1}^{1}H}}\,\] (\[n,p\]means that neutron attacks and proton liberates).
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